Sample solutions:
a) 128.100.109.26 (anything with the first three numbers the same; the last
number different; and the last number between 0 and 255)
b) 128.100.123.123 (any change to the third number, but still between 0 and
255; first two numbers still the same; fourth number doesn't matter so long
as it's between 0 and 255)
c) Two things about this, either of which would get you full marks:
- It is not a valid IP address, because two of the numbers are greater than
255. (Each of these is an eight bit number, able to represent integers
between 0 and 255 inclusive.)
- (if not for the above problem) It is apparently outside the University of
Toronto (since it doesn't start with "128.100").
(press 'back' in your web browser to get back to where you were in the exam)