Sample solutions:

a) 128.100.109.26 (anything with the first three numbers the same; the last number different; and the last number between 0 and 255)

b) 128.100.123.123 (any change to the third number, but still between 0 and 255; first two numbers still the same; fourth number doesn't matter so long as it's between 0 and 255)

c) Two things about this, either of which would get you full marks:

  1. It is not a valid IP address, because two of the numbers are greater than 255. (Each of these is an eight bit number, able to represent integers between 0 and 255 inclusive.)
  2. (if not for the above problem) It is apparently outside the University of Toronto (since it doesn't start with "128.100").

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